the length of a rectangle is 5 times its width. if the length is decreased by 3 meters, and the width is increased by 10 meters, the perimeter will be 374 meters. find the length of the original rectangle.
3 answers
2L*2W
original:
width --- x
length --- 5x , (it said so)
new dimensions:
length = 5x - 3
width = x+10
perimeter = 2* width + 2*length
= 2(x+10) + 2(5x-3) = 374
2x + 20 + 10x - 6 = 374
12x = 360
x = 30
So the original rectangle had a width of 30 m and a length of 150 m
width --- x
length --- 5x , (it said so)
new dimensions:
length = 5x - 3
width = x+10
perimeter = 2* width + 2*length
= 2(x+10) + 2(5x-3) = 374
2x + 20 + 10x - 6 = 374
12x = 360
x = 30
So the original rectangle had a width of 30 m and a length of 150 m
Thank you