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The length of a rectangle is 5 cm more than its width. What are the possible dimensions of the rectangle if the area must be at least 84 cm2? (2 marks)

1 answer

L = W + 5

L * W ≥ 84

Substitute W+5 for L in the second equation and solve for W. Insert that value into the first equation to solve for L. Check by putting both values into the second equation.
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