The length of a rectangle is 4m more than the width. The area of the rectangle is 45 m squared. Find the length and width.
Please help!
5 answers
is it 5 and 9?
width --- x
length ----x+4
x(x+4) = 45
x^2 + 4x - 45 = 0
(x+9)(x-5) = 0
x = 5 or x = a negative, which is silly
the width is 5 and the length is 9
check:
is 9 greater than 4 by 5 ? yes
is the area = 5x9 = 45 ? yes
length ----x+4
x(x+4) = 45
x^2 + 4x - 45 = 0
(x+9)(x-5) = 0
x = 5 or x = a negative, which is silly
the width is 5 and the length is 9
check:
is 9 greater than 4 by 5 ? yes
is the area = 5x9 = 45 ? yes
thanks
one more question...
the length of a rectangle is 3 times the width. the area is 108 cm squared. find the dimension of the rectangle.
the length of a rectangle is 3 times the width. the area is 108 cm squared. find the dimension of the rectangle.
just change your definitions ...
width --- x
length --- 3x
x(3x) = 108
3x^2 = 108
x^2 = 36
x = √36 = 6
back-substitute to get with and length
width --- x
length --- 3x
x(3x) = 108
3x^2 = 108
x^2 = 36
x = √36 = 6
back-substitute to get with and length
0 answers