The length of a rectangle is 4cm more than its width. If the area of the rectangle is 117cm^2, what is the length?

Question

So : 117cm^2= (w)(w+4)
= w^2 + 4w
I don't know what to do next

Answer 1

w^2 + 4 w - 117 = 0
Do you know how to use the quadratic equation?

w = [ -4 +/- sqrt (16 + 468) ] /2

w = -2 +/- (1/2) sqrt 484 )
w = -2 +/- (1/2)22
w = -2 +/- 11
use the + root
w = 9
then L = 13
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check
9 * 13 = 117 sure enough

Answer 2

Or now that I know the answer:
w^2 + 4 w - 117 = 0
(w-9)(w+13) = 0