The length of a rectangle is

4 in longer than its width. If the perimeter of the rectangle is 48 in, find its area.

6 answers

Now it's your turn.

I'll be glad to check your answer.
would I set it up like this:

48=4(4w+w)

?????
wait no... wouldn't it be 48+2(4w+w)???
48 equals 2(4w+w) not plus...
Close.

48 = 2(W + W + 4)
48 = 4W + 8
40 = 4W
10 = W
L = W + 4

P = 2 W + 2 L = 2 ( W + L ) = 48

2 ( W + W + 4 ) = 48

2 ( 2 W + 4 ) = 48 Divide both sides by 2

2 W + 4 = 24 Subtract 4 to both sides

2 W + 4 - 4 = 24 - 4

2 W = 20 Divide both sides by 2

W = 10 in

L = W + 4 = 10 + 4 = 14 in

A = L * W = 10 * 14 = 140 in ^ 2