Now it's your turn.
I'll be glad to check your answer.
The length of a rectangle is
4 in longer than its width. If the perimeter of the rectangle is 48 in, find its area.
6 answers
would I set it up like this:
48=4(4w+w)
?????
48=4(4w+w)
?????
wait no... wouldn't it be 48+2(4w+w)???
48 equals 2(4w+w) not plus...
Close.
48 = 2(W + W + 4)
48 = 4W + 8
40 = 4W
10 = W
48 = 2(W + W + 4)
48 = 4W + 8
40 = 4W
10 = W
L = W + 4
P = 2 W + 2 L = 2 ( W + L ) = 48
2 ( W + W + 4 ) = 48
2 ( 2 W + 4 ) = 48 Divide both sides by 2
2 W + 4 = 24 Subtract 4 to both sides
2 W + 4 - 4 = 24 - 4
2 W = 20 Divide both sides by 2
W = 10 in
L = W + 4 = 10 + 4 = 14 in
A = L * W = 10 * 14 = 140 in ^ 2
P = 2 W + 2 L = 2 ( W + L ) = 48
2 ( W + W + 4 ) = 48
2 ( 2 W + 4 ) = 48 Divide both sides by 2
2 W + 4 = 24 Subtract 4 to both sides
2 W + 4 - 4 = 24 - 4
2 W = 20 Divide both sides by 2
W = 10 in
L = W + 4 = 10 + 4 = 14 in
A = L * W = 10 * 14 = 140 in ^ 2
3 answers