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The length of a rectangle is

3yd less than twice the width, and the area of the rectangle is 65ydsquare. Find the dimensions of the rectangle.

1 answer

L = 2 w - 3
and
L w = 65 so L = 65/w

65/w = 2 w - 3

65 = 2 w^2 - 3 w

2 w^2 - 3w - 65 = 0

(w+5))(2w-13)

positive w = 13/2 = 6.5
etc

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