Asked by Deon
the length of a rectangle is 25cm twice its width the perimeter of the table must be less than 335 cm.find the maximum dimensions of the table if each dimension is an interger
Answers
Answered by
Reiny
width --- x
length -- 2x
2x + 2(2x) < 335
6x < 335
x < 55.8
but we can't go over 335 and x must be an integer, so
x = 55
width = 55
length = 110
check:
if w=55, l = 110 , Perimeter = 330 < 335
if w = 56, l = 112, Perimeter = 336 > 335 , no good
length -- 2x
2x + 2(2x) < 335
6x < 335
x < 55.8
but we can't go over 335 and x must be an integer, so
x = 55
width = 55
length = 110
check:
if w=55, l = 110 , Perimeter = 330 < 335
if w = 56, l = 112, Perimeter = 336 > 335 , no good
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