The length of a rectangle is 2 more than twice its width. If the area of the rectangle is 24 sq. m., find its dimensions.

1 answer

L = 2 + 2 W = 2 ( 1 + W )

A = L * W

24 = 2 * ( 1 + W ) * W

24 = 2 * ( W + W ^ 2 ) Divide both sides by 2

12 = W + W ^ 2 Subtract 12 to both sides

0 = W + W ^ 2 - 12

Now you must solwe equation :

W ^ 2 + W - 12 = 0

The exact solutions are 3 and - 4

Width cannot be negative so W = 3 m

L = 2 + 2 W

L = 2 + 2 * 3

L = 2 + 6 = 8 m

A = L * W = 8 * 3 = 24 m ^ 2

P. S.

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W ^ 2 + W - 12 = 0

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