L = 2 W + 2
L * W = 12
substituting ... W (2 W + 2) = 12 ... W^2 + W - 6 = 0
solve for W , then substitute back to find L
The length of a rectangle is 2 meters more than 2 times the width. If the area is 12 square meters, find the width and the length.
2 answers
thank you R_scott for the help.