P = 2L + 2W = 36 + 12 = 48 cm
Since you are rounding the error for each L and W < .5 cm.
With 4 sides, the should be < 2 cm.
Now, you find the percentage.
The length and breadth of a rectangular paper were measured to be the nearest centimeter and found to be 18 cm and 12 cm respectively. Find the percentage error in its perimeter.
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