let x = the width
let x+3 = the length
The area of a rectangle is length*width
x(x+3) = 54
x^2 + 3x = 54
x^2 + 3x - 54 = 0
(x+9)(x-6) = 0
x = 6, -9
A negative answer is irrelevant for this problem - the dimensions cannot be negative.
x = 6
x+3 = 9
The width is 6, and the length is 9.
thE LENGHT OF A RECTANGLE IS 3M MORE THAN ITS WIDHT .iF ITS AREA IS 54mETRE CARRE ,FIND THE DIMENSIONS OF THE RECTANGLE ?
1 answer
1 answer