The latent heat of vaporization for water is Lv = 540cal/g = 2.26*10^6 J/kg. If 300 g of water went from the room temperature, 22 degrees C, to 50 degrees C in the calorimeter, how much steam (expressed in grams) was produced?

Question

So Idk if it's a trick question cause I thought it'd be 0 g, but i was also going to use q=mc(change in T) like this:
(300)(1)(50-22) = 15.55 g of steam. Is that right or is this a trick question?