the last few times I've posted questions no one has answered them...I'm starting to get kind of upset. let's see if this one gets answered:
the perimeter of a square is 44. find the length of a diagonal.
4 answers
Use the pytagorean theorem a*2+b^2=c^2 which is 121+121=c^2 which makes 242=c^2 so the final answer would be 15.556 or just use simplest radical form
I do not see a single post by somebody called
"21 guns"
let each side of the square be x
then 4x = 44
x = 11
let the diagonal be d
by Pythagoras,
d^2 = 11^2 + 11^2 = 242
d = √242 = √121√2 = 11√2
"21 guns"
let each side of the square be x
then 4x = 44
x = 11
let the diagonal be d
by Pythagoras,
d^2 = 11^2 + 11^2 = 242
d = √242 = √121√2 = 11√2
I don't see any other posts from 21Guns. Nor do I see any other posts from your internet address in the last several hours.
44/4 = 11
To find the diagonal, use the Pythagorean theorem which gives you the hypotenuse of the right angle triangle that is formed.
a^2 + b^2 = c^2
11^2 + 11^2 = c^2
121 + 121 = 242
15.56 = c
44/4 = 11
To find the diagonal, use the Pythagorean theorem which gives you the hypotenuse of the right angle triangle that is formed.
a^2 + b^2 = c^2
11^2 + 11^2 = c^2
121 + 121 = 242
15.56 = c
thanks for your help (and it hasn't been today, it was over the last few times I have tried to get help from here)