Question

the last few times I've posted questions no one has answered them...I'm starting to get kind of upset. let's see if this one gets answered:

the perimeter of a square is 44. find the length of a diagonal.

Answer 1

Use the pytagorean theorem a*2+b^2=c^2 which is 121+121=c^2 which makes 242=c^2 so the final answer would be 15.556 or just use simplest radical form

Answer 2

I do not see a single post by somebody called
"21 guns"

let each side of the square be x
then 4x = 44
x = 11

let the diagonal be d
by Pythagoras,
d^2 = 11^2 + 11^2 = 242
d = √242 = √121√2 = 11√2

Answer 3

I don't see any other posts from 21Guns. Nor do I see any other posts from your internet address in the last several hours.

44/4 = 11

To find the diagonal, use the Pythagorean theorem which gives you the hypotenuse of the right angle triangle that is formed.

a^2 + b^2 = c^2

11^2 + 11^2 = c^2

121 + 121 = 242

15.56 = c

Answer 4

thanks for your help (and it hasn't been today, it was over the last few times I have tried to get help from here)