The largest stable nucleus has a nucleon number of 209, and the smallest has a nucleon number of 1. If each nucleus is assumed to be a sphere, what is the ratio (largest/smallest) of the surface areas of these spheres? (Area209/Area1)

Question

Please help!! I have a quiz due!!

Thanks

Answer 1

sphere volume ... 4/3 π r^3

surface area ... 4 π r^2

s.a. = k v^(2/3)

Area209 / Area1 = k[209^(2/3)] / k[1^(2/3)] = 209^(2/3)