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The larger of two numbers is 11 more than twice the smaller number the sum of the numbers is 44 find each number

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y = 11 + 2 x
x+y = 44 so x = 44 - y

y = 11 + 2 (44-y)
y = 11 + 88 - 2 y
3 y = 99
etc

Smaller number = X.
Larger number = 2x + 11.
x + (2x+11) = 44.
X = 11.
2x + 11 = 2*11 + 11 = 33.

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