Let s = smaller and L = Larger
L = 2s+1
3L = 5s+10
Substitute 2s+1 for L in second equation and solve for s. Insert that value into the first equation and solve for L. Check by inserting both values into the second equation.
the larger of two numbers is 1 more than twice the smaller. three times the larger number is 10 more than 5 times the small. find both numbers.
1 answer
1 answer