Asked by Anonymous

The Ladder is 5 m long and weighs 180N. The guy weighs 800N, and stops 1m horizontally up the ladder. The bottom of the ladder rest on a horizontal stone ledge at 53.1 degree.
Find the normal and he frictional force at the base.

HELP!!!

Answers

Answered by bobpursley
draw the figure.
lable the forces. At the top of the ladder, you have a horizontal force only pushing intothe wall, and the wall pushing back.
You have on the ladder at center, weight, and the guy 1 m upwards,
You have the base of the ladder, vertical, and friction force.

Now write equilibirum equations.
Sume horizontal forces=0
sum vertical forces =0
sum moment about any point (I recommend the base of the ladder)=0

You will get a solution quickly.
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