The laboratory technician accidentally mixed NaHCO3 with BaCl2*2H2O instead of KCl when preparing unknown mixtures for this experiment.

How would this mistake affect the calculated percentage of NaHCO3 in the mixture? Justify your answer with an explanation.

2 answers

Frankly, it makes no sense. If he accidently spilled XXX into something,why would be be calculating the percentage of XXX? It shouldn't be there at all.
I think what you mean is the unknown is supposed to be a mixture of NaHCO3 and KCl but instead it is a mixture of NaHCO3 and BaCl2.2H2O. It won't make any difference if you are determining NaHCO3 by titration with an acid.