the lab keeps two acid solutions on hand. one is 20% and the other is 35%. how much 20% and how much 35% acid solution should be used to prepare 25 liters of a 26% solution?

Answer 1

Can someone help me solve this?

Answer 2

volume of the 20% stuff ---- x L
volume of the 35% stuff ---- 25-x L

solve:

.2x + .35(25-x) = .26(25)
I suggest multiplying each term by 100 to clear the decimals.

carry on ...