The Kw of water varies with temperature. Calculate the pH of water at 46℃ with a Kw=1.219 x 10 to the negative 14th.
2 answers
Help please! I have a test next week!
(H^+)(OH^-) = Kw.
You know Kw. You know from the ionization of H2O that (H^+) = (OH^-) from H2O ==> H^+ + OH^-
Solve for (H^+) and convert to pH. I suspect you've already done this and didn't get pH = 7 so you think something is wrong. It isn't. The pH will not be 7. Why? because Kw is not 1E-14.
You know Kw. You know from the ionization of H2O that (H^+) = (OH^-) from H2O ==> H^+ + OH^-
Solve for (H^+) and convert to pH. I suspect you've already done this and didn't get pH = 7 so you think something is wrong. It isn't. The pH will not be 7. Why? because Kw is not 1E-14.