The Kw of water varies with temperature. Calculate the pH of water at 46⁰C with a Kw = 1.219 x 10-14. Show all calculations leading to an answer.
3 answers
how do I Substitute this ?
I thought I did one of these for you a couple of days ago.
...........H2O ==> H^+ + OH^-
I.........liquid....0.....0
C.........liquid....x.....x
E.........liquid....x.....x
Substitute the E line into the Kw expression and solve for x = H^+, then convert to pH.
...........H2O ==> H^+ + OH^-
I.........liquid....0.....0
C.........liquid....x.....x
E.........liquid....x.....x
Substitute the E line into the Kw expression and solve for x = H^+, then convert to pH.
I don't quite understand the last step! Can you help me? I have a test next week!. Thanks!!
1 answer