The Ksp of manganese(II) hydroxide, Mn(OH)2, is 2.00 × 10-13. Calculate the molar solubility of this compound.

Answer 1

...............Mn(OH)2 ==> Mn^2+ + 2OH^-
I..............solid.................0.............0
C............solid..................x............2x
E............solid...................x.............2x

Write the expression for Ksp for Mn(OH)2, plug in the E line above, and solve for x =-(Mn^2+)= [Mn(OH)2] and 2x = (OH^-)

Post your work if you get stuck.

Answer 2

Ksp=[Products]/[Reactants]

Mn(OH)2 -----------> Mn^+ + 2OH^-

..............Mn(OH)2 ==> Mn^2+ + 2OH^-
I..............solid.................0.............0
C............solid..................x............2x
E............solid...................x.............2x

Ksp=[x][2x]^2

Ksp=4x^3

Ksp/4=x^3

Solve for x.