To find the number of adults and children needed to attend the carnival to reach the goal of $3,500, we can set up a system of equations.
Let:
- \( x \) = number of adults
- \( y \) = number of children
From the problem, we have the following equations based on the given information:
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The total number of attendees is 500: \[ x + y = 500 \]
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The total revenue needed is $3,500. Since adults are charged $10 and children $5: \[ 10x + 5y = 3500 \]
Now we can solve this system of equations.
Step 1: Solve the first equation for one variable.
From the first equation, we can express \( y \) in terms of \( x \): \[ y = 500 - x \]
Step 2: Substitute into the second equation.
Now, substitute \( y \) in the second equation: \[ 10x + 5(500 - x) = 3500 \] Expanding this, we get: \[ 10x + 2500 - 5x = 3500 \] Combining like terms: \[ 5x + 2500 = 3500 \] Subtracting 2500 from both sides: \[ 5x = 1000 \] Dividing by 5: \[ x = 200 \]
Step 3: Find \( y \).
Now substitute \( x = 200 \) back into the equation for \( y \): \[ y = 500 - 200 = 300 \]
Thus, to reach the goal of $3,500, the PTA needs 200 adults and 300 children to attend the carnival.
Final answer: 200 adults; 300 children