To solve this problem, we can set up a system of equations based on the information provided.
Let:
- \( x \) = number of adult tickets sold
- \( y \) = number of student tickets sold
We have the following equations based on the problem statement:
-
The total number of tickets sold: \[ x + y = 375 \]
-
The total revenue collected from ticket sales: \[ 7.5x + 4.5y = 2212.50 \]
Now, we can solve this system of equations step by step.
First, from the first equation, express \( x \) in terms of \( y \): \[ x = 375 - y \]
Next, substitute this expression for \( x \) into the second equation: \[ 7.5(375 - y) + 4.5y = 2212.50 \]
Distributing \( 7.5 \): \[ 2812.5 - 7.5y + 4.5y = 2212.50 \]
Combining the \( y \) terms: \[ 2812.5 - 3y = 2212.50 \]
Subtract \( 2812.5 \) from both sides: \[ -3y = 2212.50 - 2812.5 \] \[ -3y = -600 \]
Now, divide both sides by \(-3\): \[ y = 200 \]
So, the number of student tickets sold is \( \boxed{200} \).
To confirm the result, we can find \( x \): \[ x = 375 - y = 375 - 200 = 175 \]
Now, we check the revenue: \[ 7.5x + 4.5y = 7.5(175) + 4.5(200) \] Calculating these:
- \( 7.5 \times 175 = 1312.5 \)
- \( 4.5 \times 200 = 900 \)
Now summing these two amounts: \[ 1312.5 + 900 = 2212.5 \]
Since the total matches the revenue provided in the problem, our solution is verified. Thus, the number of student tickets sold is indeed \( \boxed{200} \).