Find the mean first = sum of scores/number of scores
Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.
Standard deviation = square root of variance
SEm = SD/√n
P = .05 at ± 1.96 SEm
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability
I'll let you do the calculations.
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maximum possible rating is 10. Suppose a simple random sample of 50 business travelers is selected and each traveler is asked to provide a rating for the Miami International Airport. The ratings obtained from the sample of 50 business travelers follow.
6 4 6 8 7 7 6 3 3 8 10 4 8
7 8 7 5 9 5 8 4 3 8 5 5 4
4 4 8 4 5 6 2 5 9 9 8 4 8
9 9 5 9 7 8 3 10 8 9 6
a. Develop a 95% confidence interval estimate of the population mean rating for Miami (to 2 decimals).
95% Confidence:
1 answer
1 answer