So I used the radius of the sun....
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Only the radiation hitting the earth is intended by the statement about all the radiation REACHIN EARTH is absorbed. Use the radius of earth, not sun.
The force is then that pressure times 4 pi Rearth^2 again
You know the gravitational force on earth
F = G mass sun * mass earth / distance between squared
divide the force from part A by the gravitational force and multiply by 100 to get percent.
The intensity of sunlight reaching the earth is 1360 W/m^2
Part A:
Assuming all the sunlight is absorbed, what is the radiation-pressure force on the earth?
Give your answer in newtons.
Part B:
Give your answer as a percentage of the sun's gravitational force on the earth.
I tried for part A to do I=P/A. So I used the radius of the sun (6.955*10^8) and did (4 pi (6.955*10^8)^2 1360) to get the power then divide by the speed of light c to get my answer of 2.76*10^13 but my program said it was wrong. Part B I have no idea how to figure out.
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