The intensity of light passing through a lens can be found using the formula I=Io - Io / csc^2 theta, where Io is the intensity of the light coming in, I is the intensity of the light that emerges or goes out of the lens, and theta is the angle between. a) Find and simply and equivalent expression. b) Suppose light passes through a polarized lens at angle 3.14/4 to the original lens. How much less intense than the original light will the light be now?

Answer 1

I=Io-(I=/csc^2theta)
=Io-Io(sin^2theta)
=Io(1-sin^2theta)
=Io(cos^2theta)

For part b, assuming that it is the same type of light entering the lens, the intensity I entering should be the same. Then you can create two equations and use proportion to solve