yes, you can split it into
x/(x^2 + 9) + 3/(x^2+9)
the first part becomes
(1/2) ln(x^2 + 9)
and the second part becomes
sin^-1 (3/x) .... (had to look that one up in my old-fashioned table of integrals)
don't forget to add the constant
The integral of [(x+3)/(x^2+9)] dx
I think you split it into two fractions but im not exactly sure what to do.
3 answers
Hmmm. I get tan^-1 (x/3)
Steve, thanks for the check-up,
you are right, I must have had a senior moment.
you are right, I must have had a senior moment.