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The integral of sin(7x)cos(7x)dx

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your expression is just 1/2 sin(14x) dx

Let u=7x du/dx=7 du/7=dx therefore,1/7integral sinucosudu let v=sinu dv/du=cosu du=dv/cosu: 1/7intergralvdv=1/7v^2/2=1/14sin^2(7x)

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