inside wheel at radius r
outside wheel at radius 2 r because circumference is twice
so r = 6
so
2 pi r = 12 r
The inside wheels of a car traveling on a circular path are rotating half as fast as the outside wheels. The front two wheels are six feet apart. What is the number of feet in the path traced by the inside front wheel in one trip around the circle? Express your answer in the form "k pi", where k is an integer.
6 answers
2(2pi r) = 2pi (r+6)
2pi r = pi r + 6pi
pi r = 6pi
r = 6
so, the distance is 2pi * 6 = 12 pi
2pi r = pi r + 6pi
pi r = 6pi
r = 6
so, the distance is 2pi * 6 = 12 pi
thanks alot man!
Please do not post HW questions. Just for the record, the answer=12pi.
lmao first u sat don't that u give the answer. that's so hypocritic
Lol