To find the carrying capacity of the trailer, we need to calculate the volume of the inside space.
The volume of a rectangular box can be found by multiplying its length, width, and height.
So, the volume of Howard's semi-trailer is 52 feet × 8.25 feet × 9.25 feet = 4,828.5 cubic feet.
Therefore, the carrying capacity of the trailer is 4,828.5 cubic feet.
The inside dimensions of Howard's semi-trailer are 52 feet long, 8.25 feet wide, and 9.25 feet tall. What is the carrying capacity of the trailer?
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