The initial state of a reaction is A2 +B2 – 2AB. In the initial state of the reaction there are 6 A2’s present and 6 B2’s present. Suppose the reaction is carried out at two temperatures.Which of these situations represents the result at the higher temperature?(The reaction proceeds for the same amount of time at both temperatures)

Question

The initial state of a reaction is A2 +B2 –> 2AB.  In the initial state of the reaction there are 6 A2’s present and 6 B2’s present. Suppose the reaction is carried out at two temperatures.Which of these situations represents the result at the higher temperature?(The reaction proceeds for the same amount of time at both temperatures)
a.	2A’s, 2B’s, and 8AB’s
b.	4A’s, 4B’s, and 4AB’s

Thank You!

DrBob222 · Answer

I would think a is at the higher temperature. In a, 4 A's and 4 B's have reacted to produce 8 AB's. In b, 2A's and 2B's have reacted to produce 4 AB's. I would think that the A2's must dissociate and the B2's must dissociate then A must combine with B to form AB. The higher temperature should favor dissociation over the lower temperature and it should favor A bumping into B more often at the higher temperature. Check my thinking.