the index of refraction of h2o is 1.33. find the angle of refraction of a beam of light in air hitting the h2o surface at an angle of 60 degrees n(air)=1.00

Answer 1

Snell's Law:

Angles are measured to the normal, not surface.

SinThetaincident*nair=SinThetaRefracted*nwater

sin30*1=SinTheta*1.33

theta=arcsin .377=22 deg

Answer 2

k so the answer would b 22 degrees????