The image shows the graph of the system of linear equations {y=2x+2y=2xβˆ’4

{
𝑦
=
2
π‘₯
+
2
𝑦
=
2
π‘₯
βˆ’
4
. Which of the following points, if any, are solutions to the system of equations?

(1 point)
Responses

(0,βˆ’4)
(
0
,
βˆ’
4
)
open paren 0 comma negative 4 close paren

Neither of these points are solutions.
Neither of these points are solutions.

(0,2)
(
0
,
2
)
open paren 0 comma 2 close paren

Both of these points are solutions.

1 answer

To determine which points, if any, are solutions to the system of equations:

  1. \( y = 2x + 2 \)
  2. \( y = 2x - 4 \)

We can substitute the points to see if they satisfy both equations.

Check the point \( (0, -4) \):

Substituting \( x = 0 \) and \( y = -4 \) into both equations:

  1. First equation:
    \( y = 2(0) + 2 \)
    \( -4 = 2 \) β†’ Not true.

  2. Second equation:
    \( y = 2(0) - 4 \)
    \( -4 = -4 \) β†’ True.

Since this point only satisfies the second equation and not the first, \( (0, -4) \) is not a solution for the system.


Check the point \( (0, 2) \):

Substituting \( x = 0 \) and \( y = 2 \) into both equations:

  1. First equation:
    \( y = 2(0) + 2 \)
    \( 2 = 2 \) β†’ True.

  2. Second equation:
    \( y = 2(0) - 4 \)
    \( 2 = -4 \) β†’ Not true.

Since this point only satisfies the first equation and not the second, \( (0, 2) \) is not a solution for the system.


Since neither point is a solution, the correct response is:

Neither of these points are solutions.