To determine if the points (0, 2) and (0, -4) are solutions to the system of equations given by \( y = 2x + 2 \) and \( y = 2x - 4 \), we will substitute the x-coordinates of each point into each equation and see if the corresponding y-values match.
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For the point (0, 2):
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Substitute \(x = 0\) into the first equation \(y = 2x + 2\): \[ y = 2(0) + 2 = 2 \] The point (0, 2) satisfies the first equation.
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Now substitute \(x = 0\) into the second equation \(y = 2x - 4\): \[ y = 2(0) - 4 = -4 \] The point (0, 2) does not satisfy the second equation.
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For the point (0, -4):
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Substitute \(x = 0\) into the first equation \(y = 2x + 2\): \[ y = 2(0) + 2 = 2 \] The point (0, -4) does not satisfy the first equation.
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Now substitute \(x = 0\) into the second equation \(y = 2x - 4\): \[ y = 2(0) - 4 = -4 \] The point (0, -4) satisfies the second equation.
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Conclusion:
- The point (0, 2) is a solution to the first equation but not to the second equation.
- The point (0, -4) is a solution to the second equation but not to the first equation.
Therefore, the correct response is: Neither of these points are solutions.