To complete the division process of \( (3x^4 + 9x^2 - 13) ÷ (x^2 - 5x) \) using polynomial long division, we will divide step by step.
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Set up the division: Divide Polynomial \(3x^4 + 0x^3 + 9x^2 - 13\) by \(x^2 - 5x\).
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First term: Divide \(3x^4\) by \(x^2\) to get \(3x^2\).
- Multiply \(3x^2\) by the divisor \(x^2 - 5x\): \[ 3x^2(x^2 - 5x) = 3x^4 - 15x^3 \]
- Subtract this from the original polynomial: \[ (3x^4 + 0x^3 + 9x^2) - (3x^4 - 15x^3) = 15x^3 + 9x^2 \]
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Next term: Divide \(15x^3\) by \(x^2\) to get \(15x\).
- Multiply \(15x\) by \(x^2 - 5x\): \[ 15x(x^2 - 5x) = 15x^3 - 75x^2 \]
- Subtract this from \(15x^3 + 9x^2\): \[ (15x^3 + 9x^2) - (15x^3 - 75x^2) = 84x^2 \]
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Next term: Divide \(84x^2\) by \(x^2\) to get \(84\).
- Multiply \(84\) by \(x^2 - 5x\): \[ 84(x^2 - 5x) = 84x^2 - 420x \]
- Subtract this from \(84x^2\): \[ (84x^2) - (84x^2 - 420x) = 420x \]
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Since the degree of the remaining polynomial \(420x\) is less than the degree of the divisor \(x^2 - 5x\), we stop here.
Therefore, the result of the division can be expressed as:
\[ 3x^2 + 15x + 84 + \frac{420x}{x^2 - 5x} \]
Thus, the remainder is:
\[ \text{Remainder } = 420x \]
From the options provided, the correct answer is:
The remainder is \(420x\).