Asked by Alexa
The hypotenuse of a right triangle has length 8. The area of the triangle is also 8 units squared. What is the perimeter of the triangle?
Answers
Answered by
Steve
c^2 = a^2+b^2 = 64
ab/2 = 8
(a+b)^2 = a^2+2ab+b^2 = 8+32 = 40
p = a+b+c = 8+√40
ab/2 = 8
(a+b)^2 = a^2+2ab+b^2 = 8+32 = 40
p = a+b+c = 8+√40
Answered by
Alexa
Thanks Steve, but how do you get to this step?
(a+b)^2 = a^2+2ab+b^2 = 8+32 = 40
(a+b)^2 = a^2+2ab+b^2 = 8+32 = 40
Answered by
Steve
Good catch. a^2+b^2 = 64, not 8
Answered by
Alexa
But still not sure how you come up with this formula
(a+b)^2 ?
(a+b)^2 ?
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