The hydroxide of metal y reacts with hydrochloric acid as follow
Y(OH)2+2HCL product YCl2+2H20
It was found that 5.8g of Y(0H)2 reacted with 0.2M hydrochloric acid .calculate the a) molar mass of Y(0H)2
B)atomic mass of y
4 answers
Please anyone help me collect way to answer step by step
a.
Y(OH)2 + 2HCl ==> YCl2 + 2H20
mols HCl = M x L = ?
You don't have enough information. You didn't give the amout of 0.2 M HCl used in the reaction.
Y(OH)2 + 2HCl ==> YCl2 + 2H20
mols HCl = M x L = ?
You don't have enough information. You didn't give the amout of 0.2 M HCl used in the reaction.
Molarity of HCL= 0.2M
Number of Mole = Molarity x Volume of solution
= 0.2 x 1dm³
=0.2M
Number of mole = 0.2 ÷2 = 0.1mole
Molarmass = Mass/Number of Mole
= 58g/mol.
Y(OH)2 =58g/mol
Y + 34= 58 g/mol
Y= 24.
Number of Mole = Molarity x Volume of solution
= 0.2 x 1dm³
=0.2M
Number of mole = 0.2 ÷2 = 0.1mole
Molarmass = Mass/Number of Mole
= 58g/mol.
Y(OH)2 =58g/mol
Y + 34= 58 g/mol
Y= 24.
Help is needed step by step
0 answers