The hydrostatic equation holds not just for air, but for other fluids such as water (air, though it is a gas, is often referred to as a 'fluid') as well. In the case of water the equation becomes even easier, as water (as opposed to air) can be treated as incompressible, meaning the density is constant. Use a value of 1000 kilogram per cubic metre as density.

Using this information, compute the local pressure (in [Pa]) at 2.5 metres depth in a swimming pool situated at 2400 metres altitude in the mountains. Assume a standard atmosphere.

3 answers

The pressure will be 1*2.5/10 atmospsheres below the atmospheric pressure at the surface of the pool.
At 2400 meters altitude, atmospheric pressure should be p = 101325 (1 - 2.25577e-5 h)^5.25588 or
p=101325(1-2.25577e-5*2400)^5.25588=75625Pa
so, pressure 2.5m below surface should be 75.6kPa-2.5*101.3/10 kPa
=50.3 kPa
ur supposed to add the nearly 25kpa tot the 75.6kpa so the answer should be around 100139.2 pa
100139.2 is the correct answer.