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The hydroperoxide ion, HO2–(aq), reacts with permanganate ion, MnO4–(aq) to produce MnO2(s) and oxygen gas. Balance the equation for the oxidation of hydroperoxide ion to O2(g) by permanganate ion in a basic solution.

2 answers

HO2^- = + OH^- => O2 + 2e + H2O
MnO4^- + 3e + 2H2O==> MnO2 + 4OH^-

Here are the two balanced half equations. Multiply eqn 1 by 3 and multiply eqn 2 by 2 then add the two equations. Finally, cancel anything that appears on both sides of the final equation. Post your work if you get stuck.
Why are the 3e + 2H2O added ?
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