HO2^- = + OH^- => O2 + 2e + H2O
MnO4^- + 3e + 2H2O==> MnO2 + 4OH^-
Here are the two balanced half equations. Multiply eqn 1 by 3 and multiply eqn 2 by 2 then add the two equations. Finally, cancel anything that appears on both sides of the final equation. Post your work if you get stuck.
The hydroperoxide ion, HO2–(aq), reacts with permanganate ion, MnO4–(aq) to produce MnO2(s) and oxygen gas. Balance the equation for the oxidation of hydroperoxide ion to O2(g) by permanganate ion in a basic solution.
2 answers
Why are the 3e + 2H2O added ?