Tension in string 1= forces to left=forces to right
I am going to make force, acceleration to the right as +.
writing force equation:
3F-2F=totalmass*a
F=(6*a)
a= 12/6=2m/s^2
Now for tension. 3F-tension1= net force on block3m=3M*a
or Tension1=3*12-3(2)(2)=36-12=24N
now looking at the same forces from the left
-3F-M(a)-2M(a)=tension1
-36-4-8=-24=tiension1
so the left meansure of tension1 is the same as the right, 24N.
The horizontal surface on which the objects slide is frictionless. If F = 12 N and M = 2kg, (a) what is the tension in string 1? (b) What is the acceleration of the system?
<--2F--blockM--2--block2M--1--block3M--3F-->
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