The home states of a certain group of people are distributed as follows: 53 percent are from MISSOURI, 21 percent are from KANSAS, and 26 percent are from IOWA. (No one in the group had a home state other than one of these three.)
(Note: Your answer to the question below should be rounded to three decimal places.)
Suppose we randomly select a person from this group. What is the expected value of the number of letters in the selected person's home state?
4 answers
5.54134
(53*8)+(21*6)+(26*4)= 654
654/100= 6.54 letters
654/100= 6.54 letters
6.64
oops I read this from my textbook where the values are a bit different.
Please ignore my misinformation world.
Please ignore my misinformation world.
1 answer