The highest barrier that a projectile can clear is 18.8 m, when the projectile is launched at an angle of 59.0 ° above the horizontal. What is the projectile's launch speed?

Answer 1

do vertical problem with conservation of energy first:
(1/2) m Vi^2 = m g h
.5 Vi^2 = 9.81 * 18.8
Vi = 19.2 m/s initial speed up
sin 59 = 19.2 / s
s = 22.4 m/s