The height of building AB is 100 feet. The height of building CD is 50 feet. The buildings are on opposite sides of an avenue that is 90 feet wide. From a point E on the avenue, the measure of the angle of elevation to B is 55º. Determine the distance from E to D to the nearest foot.

Answer 1

As always, draw your diagram. It should be clear that

EA = 100 cot55º
Now, (90-EA)^2 + 50^2 = ED^2