The height of an equilateral triangle equals 3√2 times the side length. Using 74 for the square root of 3, what is the approximate height in meters of an equilateral triangle with a side length of 8 meters?(1 point)

1 answer

To find the height of an equilateral triangle given that the height equals \(3\sqrt{2}\) times the side length, we can use the following formula:

\[ \text{Height} = 3\sqrt{2} \times \text{side length} \]

Given that the side length of the triangle is 8 meters, we can substitute this value into the formula:

\[ \text{Height} = 3\sqrt{2} \times 8 \]

Now we can calculate the height:

\[ \text{Height} = 24\sqrt{2} \]

Next, we will use the approximate value of \(\sqrt{2}\):

\[ \sqrt{2} \approx 1.414 \]

Now we can calculate the height:

\[ \text{Height} \approx 24 \times 1.414 \]

Calculating that gives:

\[ \text{Height} \approx 33.936 \]

Therefore, the approximate height in meters of the equilateral triangle is:

\[ \text{Height} \approx 33.94 \text{ meters} \]

Thus, the final answer for the height of the equilateral triangle with a side length of 8 meters is approximately 33.94 meters.