The height of an air column is proportional to the volume of air contained in the capillary tube. Therefore, use the height of the air column as the value for the volume of the gas, and calculate the volume/temperature ratio for each trial .
Here are the heights for the air columns:
4.8 cm
5.2 cm
5.4 cm
5.8 cm
6.2 cm
6.5 cm
I'm not sure how to calculate the volume/temperature ratio.Please help!
Do you have temperatures for each of the heights you measured? Then 4.8/T; 5.2/T, etc.
I don't know what experiment you are doing but T MAY need to be in Kelvin.
I am doing experiment 24 in the Prentice Hall lab book if that helps. Anyways I have temperatures in celsius and kelvin.Here is the chart:
Temp. Height Temp in K
in C:
1.1 4.8 274.25
23.2 5.2 296.35
40.1 5.4 313.25
61.4 5.8 334.55
79.0 6.2 352.15
99.9 6.5 373.05
So would I for example put 4.8/274.25, 5.2/296.35, etc. for the volume temperature ratios?
I haven't seen a copy of the Prentice-Hall lab book so that doens't help much. Since you also asked the question about why graph in both C and K, I would suggest you determine both ratios; i.e., 4.8/1.1 and 4.8/274.25.