avg velocity= distance/time
= (height(t=3)-height(t=2)/(3-2)
instantaneous velocity? df/dt=2t+2
The height of a particle is given by the equation f(t)=t^2+2t+6
(a) What is the average velocity of the particle on the interval [2,3]?b.What is its instantaneous velocity at t = 2.
What is the instantaneous velocity of the object at any time t?
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