The height of a ball thrown upward on the moon with a velocity of 8 meters per second can be modeled by h=-0.8t^2+8t, where h is the height of the ball in meters and t is the time in seconds. At what times will the height of the ball reach 19.2 meters

1 answer

just solve
-0.8t^2+8t = 19.2
using the quadratic formula

Or, to make things a bit simpler,
8t^2 - 80t + 192 = 0
t^2 - 10t + 24 = 0
which you can easily factor