The height of a ball thrown straight up into the air as a function of time is given as h(t) = 1 + 15t Ð 4.9t^2. At what time does the ball hit the ground?

Answer 1

At ground level, h = 0
1+15t-4.9t^2 = 0
4.9t^2 - 15t - 1 = 0

Solve using the quadratic equation, using only the positive solution.

Answer 2

Thanks Reiny