The height (in meters) of a projectile shot vertically upward from a point 3 m above ground level with an initial velocity of 21.5 m/s is

h = 3 + 21.5t − 4.9t2
after t seconds. (Round your answers to two decimal places.)

a. When does it hit the ground?

I set the equation equal to 0, yet I am not sure what to do since there is a number 3 in the equation, usually it's easy to simplify.

1 answer

you are solving

4.9t^2 - 21.5t - 3 = 0 , after multiplying each term by -1

You must have learned the quadratic equation to be solving these type of questions, go ahead.